The purpose of this lab is to simplify a complex circuit by using Thevenin Equivalent method. We were given the engineering problem of finding the smallest equivalent load resistance that can be used in a system of multiple sources and loads. Using Thevenin Equivalent, only VTh, RTh, and Rload 2. Therefore, using nodal analysis, we calculated Vth = 8.64V and I load 2 = 0.131 A, and found RTh with RTh = VTh/ I load 2 = 66 Ω, RL2 = 825 Ω.
Results
Config Theoretical Value Measured Value % error
RL2 Vload2 = 8V 7.99V 0.13%
RL2 infi. Vload2 =8.64V 8.63V 0.12%
Extra
Pmax = 8.64^2/(4*66)=0.28W
Overall, values were fairly close with both circuits. Percent error may have been the result of using 9.07V for power sources instead of an ideal 8V.
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